document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1150167>Question 1150167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A person starts walking from home and walks:<BR>\n" );
document.write( "6 miles East<BR>\n" );
document.write( "4 miles Southeast<BR>\n" );
document.write( "4 miles South<BR>\n" );
document.write( "6 miles Southwest<BR>\n" );
document.write( "3 miles East\r<BR>\n" );
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document.write( "This person has walked a total of (answer) miles\r<BR>\n" );
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document.write( "Find the total displacement vector for this walk: <BR>\n" );
document.write( "   <BR>\n" );
document.write( "If this person walked straight home, they'd have to walk (answer) miles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #771577 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=771577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do this on a cartesian coordinate system<BR>\n" );
document.write( "He goes from the origin to (6, 0) the 45 degrees southeast, which is 4/sqrt(2) or 2 sqrt(2) units positive x and negative y.  That is (8 sqrt(2),-2 sqrt(2)) then 4 units south to ( 8 sqrt(2), -6 sqrt(2))<BR>\n" );
document.write( "southwest 6 is x negative and y negative 3 sqrt(2) for each to (5 sqrt(2), -9 sqrt (2))<BR>\n" );
document.write( "3 east is (8 sqrt(2), -9 sqrt(2))\r<BR>\n" );
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document.write( "They walked 23 miles total<BR>\n" );
document.write( "they went from (0, 0) to (8 sqrt(2), -9 sqrt(2))<BR>\n" );
document.write( "The tangent of theta, the angle from east to south, is 9 sqrt(2)/8 sqrt(2)=9/8<BR>\n" );
document.write( "arc tan of that is 48.37 degrees or 138.47 degrees, a little south of SSE.\r<BR>\n" );
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document.write( "The straight home distance is the sqrt of those two coordinates squared or <BR>\n" );
document.write( "sqrt(128+162)=sqrt(290)=17.03 miles </SPAN>\n" );
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