document.write( "Question 1150159: How many different perfect squares are factors of 2007^2007? \n" ); document.write( "
Algebra.Com's Answer #771517 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "(corrected response, thanks to tutor @ikleyn for pointing out the obvious error....)
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\n" ); document.write( "The sum of the digits of 2007 is 9, so the number is divisible by 9:

\n" ); document.write( "\"2007+=+3%2A3%2A223\"

\n" ); document.write( "223 is prime, so we have the prime factorization of 2007:

\n" ); document.write( "\"2007+=+%283%5E2%29%28223%5E1%29\"

\n" ); document.write( "Then

\n" ); document.write( "\"2007%5E2007+=+%283%5E4014%29%28223%5E2007%29\"

\n" ); document.write( "A perfect square factor of the number has to be of the form

\n" ); document.write( "\"%283%5Ea%29%28223%5Eb%29\"

\n" ); document.write( "Where a and b are even integers, with 0 <= a <= 4014 and 0 <= b <= 2007.

\n" ); document.write( "That gives us 2008 choices for a and \"cross%282007%29\" 1004 choices for b; the number of perfect square factors of the number is then \"cross%282008%2A2007+=+4030056%29\" 2008*1004 = 2016032.
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