document.write( "Question 1150062: Maricopa's Success scholarship fund receives a gift of $130000. The money is invested in stocks, bonds, and CDs. CDs pay 2.5 % interest, bonds pay 5.5 % interest, and stocks pay 10.5 % interest. Maricopa Success invests $35000 more in bonds than in CDs. If the annual income from the investments is $10600, how much was invested in each account?\r
\n" );
document.write( "\n" );
document.write( "Maricopa Success invested $____ in stocks. Maricopa Success invested $____ in bonds. Maricopa Success invested $____ in CDs. \n" );
document.write( "
Algebra.Com's Answer #771475 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! CDs: \n" ); document.write( "Principal = p \n" ); document.write( "Rate = 0.025 \n" ); document.write( "Interest = 0.025p \n" ); document.write( " \n" ); document.write( "Bonds: \n" ); document.write( "Principal = p + 35000 \n" ); document.write( "Rate = 0.055 \n" ); document.write( "Interest = 0.055(p + 35000) = 0.055p + 1925 \n" ); document.write( " \n" ); document.write( "Stocks: \n" ); document.write( "Principal = 130000 - (p) - (p + 35000) = 95000 - 2p \n" ); document.write( "Rate = 0.105 \n" ); document.write( "Interest = 0.105(95000 - 2p) = 9975 - 0.21p \n" ); document.write( " \n" ); document.write( "(0.025p) + (0.055p + 1925) + (9975 - 0.21p) = 10600 \n" ); document.write( " \n" ); document.write( "-0.13p + 11900 = 10600 \n" ); document.write( " \n" ); document.write( "-0.13p = -1300 \n" ); document.write( " \n" ); document.write( "p = 10000 \n" ); document.write( " \n" ); document.write( "CDs: \n" ); document.write( "Principal = p = $10,000 \n" ); document.write( " \n" ); document.write( "Bonds: \n" ); document.write( "Principal = p + 35000 = 10000 + 35000 = $45,000 \n" ); document.write( " \n" ); document.write( "Stocks: \n" ); document.write( "Principal = 95000 - 2p = 95000 - 20000 = $75,000 |