document.write( "Question 106033This question is from textbook functions modeling change
\n" ); document.write( ": How long does it take an investment to double if it grows according to the formula V=537e^.015t? Assume t is in years? (^ is used to show that e has been raised to the .015t power). \n" ); document.write( "
Algebra.Com's Answer #77147 by Fombitz(32388)\"\" \"About 
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At time t=0, the investment is worth V=$537
\n" ); document.write( "When will it be worth 2($537)=$1074?
\n" ); document.write( "\"V%28t%29=1074\"
\n" ); document.write( "\"537e%5E%28.015t%29=1074\"Substitute with the formula.
\n" ); document.write( "\"e%5E%28.015t%29=2\"Divide by 537.
\n" ); document.write( "\".015t=ln%282%29\"Natural log of both sides.
\n" ); document.write( "\"t=ln%282%29%2F.015\"Divide by .015.
\n" ); document.write( "t=46.2 years\r
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