document.write( "Question 1150082: Find the value of x that makes the following equation true:\r
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Algebra.Com's Answer #771443 by ikleyn(52799)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Introduce new variable  t = \"sqrt%283x%29\" + \"sqrt%283%2Fx%29\".                            (1)\r\n" );
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document.write( "Notice that by its meaning  (1), t is a positive real number.    (*)\r\n" );
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document.write( "Your equation then takes the form\r\n" );
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document.write( "    \"%28t-2sqrt%283%29%29%2Ft\" = \"t%2F%28t%2Bsqrt%283%29%29\".\r\n" );
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document.write( "Next cross-multiply\r\n" );
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document.write( "    \"%28t-2sqrt%283%29%29%2A%28t%2Bsqrt%283%29%29\" = \"t%5E2\"\r\n" );
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document.write( "    \"t%5E2+-+%28sqrt%283%29%29%2At+-+6\" = \"t%5E2\"\r\n" );
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document.write( "      t = - \"6%2Fsqrt%283%29\" = - \"2%2Asqrt%283%29\".    (2)\r\n" );
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document.write( "Now you see that t, expressed as (2), is a negative number.\r\n" );
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document.write( "It contradicts to the notice (*) above that t should be positive.\r\n" );
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document.write( "Hence, the original equation HAS NO SOLUTIONS.      A N S W E R\r\n" );
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document.write( "Plot y =  (left side, red), y =   (right side, green)\r\n" );
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