document.write( "Question 1150052: A movie theater has a seating capacity of 287. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults. There are half as many adults as there are children. If the total ticket sales was $ 2072 on a sold out night, how many children, students, and adults attended? \n" ); document.write( "

Algebra.Com's Answer #771408 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Let x be the number of adults.\r\n" );
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document.write( "Then the number of children is 2x  and the number of students is (287-x-2x) = 287 - 3x.\r\n" );
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document.write( "Now you can write the equation for total money\r\n" );
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document.write( "    5*(2x) + 7*(287-3x) + 12*x = 2072.\r\n" );
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document.write( "Simplify and solve for x\r\n" );
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document.write( "     10x + 7*287 - 21x + 12x = 2072\r\n" );
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document.write( "       x                     = 2072 - 7*287 = 63.\r\n" );
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document.write( "ANSWER.  63 adults, 2*63 = 126 children and  287-63-126 = 98 students.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The lesson to learn from my solution is THIS :\r
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document.write( "    This problem is to be solved using one equation and one unknown.\r\n" );
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