document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1150030>Question 1150030</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x^(2)+6x+7 in vertex form<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #771377 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=771377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is (x+3)^2-2\r<BR>\n" );
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document.write( "you do this by finding the x-value vertex of the function, which is x=-b/2a, or 6/-2 or -3\r<BR>\n" );
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document.write( "when x=-3, the function has value 9-18+7, or -2\r<BR>\n" );
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document.write( "Now put in vertex form which changes the sign of h, or -3 to +x and keeps the value of k above, or -2\r<BR>\n" );
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document.write( "(x-h)^2+k  or (x+3)^2-2  ANSWER\r<BR>\n" );
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document.write( "that is x^2+6x+9-2 or x^2+6x+7 </SPAN>\n" );
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