document.write( "Question 1149902: a trader sales a bag of beans for sh.2,100.00 and that of maize for sh.1,200.00. he mixed beans and maize in the ratio 3:2. find how much the trader should sell a bag of the mixture to realize the same profit \n" ); document.write( "

Algebra.Com's Answer #771371 by ikleyn(52790) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "            I will assume that when the trader mixes \"x\" bags of beans with \"y\" bags of maize, he gets x+y bags of the mixture.\r
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\n" ); document.write( "\n" ); document.write( "            I specially underline this assumption, because when somebody mixes granular materials, the volume of the mixture
\n" ); document.write( "            is NOT NECESSARY equal to the sum of volumes of ingredients.\r
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\n" ); document.write( "\n" ); document.write( "            With this assumption, the solution is as follows.\r
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document.write( "If the trader mixes 3 bags of beans with 2 bags of maize, the cost of the 5 bags of the mixture is  3*2100 + 2*1200 = 8700 sh.\r\n" );
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document.write( "So, to realize the same profit, the trader must sell each bag of the mixture at the price   = 1740 sh.    ANSWER\r\n" );
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