document.write( "Question 1149982: how do you solve 3cos^2x=2sin^2x+2
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Algebra.Com's Answer #771321 by greenestamps(13209) $\"\"$ $\"About$

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\n" ); document.write( "Replace cos^2x with 1-sin^2x to obtain a quadratic equation in sinx; or replace sin^2x with 1-cos^2x to obtain a quadratic equation in cosx.

\n" ); document.write( "Then solve the quadratic in sinx or cosx exactly the same way you would solve a quadratic in x.

\n" ); document.write( " $\"3%28cosx%29%5E2+=+2%28sinx%29%5E2%2B2\"$
\n" ); document.write( " $\"3%28cosx%29%5E2+=+2%281-%28cosx%29%5E2%29%2B2\"$
\n" ); document.write( " $\"3%28cosx%29%5E2+=+2-2%2Acos%28x%29%5E2%2B2+=+4-2%2Acos%28x%29%5E2\"$
\n" ); document.write( " $\"5%28cos%28x%29%5E2%29+=+4\"$
\n" ); document.write( " $\"cos%28x%29%5E2+=+4%2F5\"$

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