document.write( "Question 1149918: A student bought 3 boxes of pencils and 2 boxes of pens for $6. He then bought 2 boxes of pencils and 4 boxes of pens for $8. Find the cost of each box of pencils and each box of pens. \n" ); document.write( "
Algebra.Com's Answer #771260 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First, a solution by logical reasoning.... \n" ); document.write( "Let's change the statement of the problem a bit so that the two purchases are by different students. That will make it easier to describe the method for solving the problem. \n" ); document.write( "So we have \n" ); document.write( "Student A: 3 boxes of pencils and 2 boxes of pens for $6. \n" ); document.write( "Student B: 2 boxes of pencils and 4 boxes of pens for $8. \n" ); document.write( "Student B bought twice as many boxes of pens as student A. So consider a third student C buying twice as much as student A, so that students B and C buy the same numbers of boxes of pens. \n" ); document.write( "Student C: 6 boxes of pencils and 4 boxes of pens for $12. \n" ); document.write( "Now compare the purchases by students B and C. They bought the same number of boxes of pens; student C bought 4 more boxes of pencils than student B, and his cost was $4 more. So each box of pencils costs $1. \n" ); document.write( "Then use the purchases of any one of the three students to find that the cost of each box of pens is $1.50. \n" ); document.write( "Now a typical algebraic solution, which follows the exact same path as the solution above. \n" ); document.write( "[1] \n" ); document.write( "[2] \n" ); document.write( "[3] \n" ); document.write( "[4] \n" ); document.write( "[5] \n" ); document.write( "[6] \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |