document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1149894>Question 1149894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A paint dealer mixes three types of paint A, B and C in the ratios A:B = 3:4 and B:C = 1:2. the mixture is to contain 168 litres of C .  A)find the ratio A:B:C<BR>\n" );
document.write( "B) Find the required number of litres of B<BR>\n" );
document.write( "C)The cost per litre of type A is sh.160, type B is sh.205 and type c is sh.100 . i) calculate the cost per liter of the mixture <BR>\n" );
document.write( "ii) find the percentage profit if the selling price of the mixture is sh.182 per liter. iii) find the selling price of a liter of the mixture if the dealer makes a 25% (profit?). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #771239 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=771239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the ratios are:<BR>\n" );
document.write( "A:B = 3:4<BR>\n" );
document.write( "this ratio says that, for every 3 parts of A, you have 4 parts of B.<BR>\n" );
document.write( "B:C = 1:2<BR>\n" );
document.write( "this ratio says that, for every 1 part of B, you have 2 parts of C.\r<BR>\n" );
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document.write( "to combine these 2 ratios into 1 overall ratio, you need 4 parts of B.<BR>\n" );
document.write( "the corresponding ratio of B:C would be B:C = 4:8.<BR>\n" );
document.write( "the overall ratio becomes A:B:C = 3:4:8<BR>\n" );
document.write( "this ratio says that for every 3 parts of A, you have 4 parts of B and for every 4 parts of B, you have 8 parts of C.\r<BR>\n" );
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document.write( "if the mixture contains 168 liters of C, divided that by 8 and multiply it by 4 to get 84 liters of B.   divide that by 4 and multiply it by 3 to get 63 liters of A.\r<BR>\n" );
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document.write( "you have 63 liters of A and 84 liters of B and 168 liters of C.\r<BR>\n" );
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document.write( "the ratio of A:B is 3:4.<BR>\n" );
document.write( "A:B = 3:4 can be written as A/B = 3/4.<BR>\n" );
document.write( "solve for B to get B = 4/3 * A.<BR>\n" );
document.write( "this makes B = 4/3 * 63 = 84.\r<BR>\n" );
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document.write( "the ratio of B:C is 1:2.<BR>\n" );
document.write( "this can be written as B/C  1/2.<BR>\n" );
document.write( "solve for C to get C = 2 * B<BR>\n" );
document.write( "this makes C = 2 * 84 = 168\r<BR>\n" );
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document.write( "note that A:B = 3:4 can also be written as A/B = 3/4.<BR>\n" );
document.write( "note that B:C = 1:2 can also be written as B/C = 1/2.<BR>\n" );
document.write( "not also that B/C = 1/2 is equivalent to B/C = 4/8 which can also be written as B:C = 4:8.<BR>\n" );
document.write( "you have A:B = 3:4 and B:C = 4:8 which can then be written as A:B:C = 3:4:8.\r<BR>\n" );
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document.write( "we have:<BR>\n" );
document.write( "A = 63<BR>\n" );
document.write( "B = 84<BR>\n" );
document.write( "C = 168\r<BR>\n" );
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document.write( "the cost per liter of type A is 160.<BR>\n" );
document.write( "the cost per liter of type B is 205.<BR>\n" );
document.write( "the cost per liter of type C is 100.\r<BR>\n" );
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document.write( "assuming 168 liters of type C, then the overall cost of the mixture would be:<BR>\n" );
document.write( "160 * 63 + 205 * 84 + 100 * 168 = 44100.<BR>\n" );
document.write( "divide that by the total liters of 63 + 84 + 168 = 315 and the overall cost per liter of the mixture is 44100 / 315 = 140.\r<BR>\n" );
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document.write( "if the selling price of the mixture is 182, then the percent profit = (182-140)/140 * 100 = 30%.\r<BR>\n" );
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document.write( "if the dealer wants to make a 25% profit, then the equation for that is 25% = (x - 140) / 140 * 100.<BR>\n" );
document.write( "divide both sides of this formula by 100 to get:<BR>\n" );
document.write( ".25 = (x - 140) / 140<BR>\n" );
document.write( "multiply both sides of this formula by 140 to get:<BR>\n" );
document.write( "35 = x - 140<BR>\n" );
document.write( "solve for x to get x = 175.\r<BR>\n" );
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document.write( "the dealer would have to make the selling price equal to 175 so that the dealer can make a 25% profit.<BR>\n" );
document.write( "(175 - 140) / 140 * 100 = 25%.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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