document.write( "Question 1149892: From a collection of 51 store customers, 3 are to be chosen to receive a special gift. How many groups of 3 customers are possible? \n" ); document.write( "
Algebra.Com's Answer #771229 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "\"51 choose 3\"

\n" ); document.write( "\"C%2851%2C3%29+=+%2851%2A50%2A49%29%2F%283%2A2%2A1%29+=+20825\"

\n" ); document.write( "Anyone of the 51 can be chosen first; any of the remaining 50 second; and any of the remaining 49 third. So 51*50*49 different ORDERS in which 3 of the 51 can be chosen.

\n" ); document.write( "But for any given group of 3, the number of different orders in which they could have been chosen is 3*2*1.

\n" ); document.write( "So the number of different COMBINATIONS of 3 chosen from 51 is (51*50*49)/(3*2*1).

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