document.write( "Question 1149883: 49^x-1=7√7 \n" ); document.write( "

Algebra.Com's Answer #771217 by greenestamps(13203) $\"\"$ $\"About$

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\n" ); document.write( "Use parentheses where required!

\n" ); document.write( "What you wrote; surely not what you intended: \"49^x-1 = 7*sqrt(7)\" --> $\"49%5Ex-1+=+7%2Asqrt%287%29\"$

\n" ); document.write( "What you undoubtedly meant: \"49^(x-1) = 7*sqrt(7)\" --> $\"49%5E%28x-1%29+=+7%2Asqrt%287%29\"$

\n" ); document.write( "In the correct form, the equation is easily solved by expressing both sides of the equation as powers of 7:

\n" ); document.write( " $\"49%5E%28x-1%29+=+7%2Asqrt%287%29\"$
\n" ); document.write( " $\"%287%5E2%29%5E%28x-1%29+=+7%2A7%5E%281%2F2%29\"$
\n" ); document.write( " $\"7%5E%282x-2%29+=+7%5E%283%2F2%29\"$

\n" ); document.write( "The bases are the same; if the expressions are equal, then the exponents are equal.

\n" ); document.write( " $\"2x-2+=+3%2F2\"$
\n" ); document.write( " $\"2x+=+2%2B3%2F2+=+7%2F2\"$
\n" ); document.write( " $\"x+=+7%2F4\"$

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