document.write( "Question 1149873: A flower bed is in the shape of a triangle with one side twice the length of the shortest side and the third side is
\n" ); document.write( "16
\n" ); document.write( "16 feet more than the length of the shortest side. Find the dimensions if the perimeter is
\n" ); document.write( "172
\n" ); document.write( "172 feet.
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Algebra.Com's Answer #771205 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "A flower bed is in the shape of a triangle: so, the perimeter is \r
\n" ); document.write( "\n" ); document.write( "\"P=a%2Bb%2Bc\" where \"a\" is the shortest side, and \"b\" is other side twice the length of the shortest side and the third side \"c\" is \"16\" feet more than the length of the shortest side. \r
\n" ); document.write( "\n" ); document.write( "so, sides are:\r
\n" ); document.write( "\n" ); document.write( "\"a\"
\n" ); document.write( "\"b=2a\"
\n" ); document.write( " \"c=a%2B16\"\r
\n" ); document.write( "\n" ); document.write( "Find the dimensions if the perimeter is \"172\" feet.\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"P=172\", \"a\", \"b=2a\",\"c=a%2B16\"\r
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\n" ); document.write( "\n" ); document.write( "so, we have\r
\n" ); document.write( "\n" ); document.write( "\"172=a%2B2a%2Ba%2B16\" .........solve for \"a\"\r
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\n" ); document.write( "\n" ); document.write( "\"172=4a%2B16\"\r
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\n" ); document.write( "\n" ); document.write( "\"172-16=4a\"\r
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\n" ); document.write( "\n" ); document.write( "\"156=4a\"\r
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\n" ); document.write( "\n" ); document.write( "\"156%2F4=a\"\r
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\n" ); document.write( "\n" ); document.write( "\"a=highlight%2839%29\"->the shortest side\r
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\n" ); document.write( "\n" ); document.write( "\"b=2a\"->\"b=highlight%2878%29\"->other side\r
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\n" ); document.write( "\n" ); document.write( "\"c=a%2B16\"->\"c=39%2B16\"->\"c=highlight%2855%29\"->the third side\r
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\n" ); document.write( "\n" ); document.write( "check the perimeter:\r
\n" ); document.write( "\n" ); document.write( "\"172=a%2Bb%2Bc\"\r
\n" ); document.write( "\n" ); document.write( "\"172=39%2B78%2B55\"\r
\n" ); document.write( "\n" ); document.write( "\"172=172\"\r
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