document.write( "Question 105991This question is from textbook Precalculus
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\n" ); document.write( "\n" ); document.write( "cos theta sec theta/cot theta = tan theta\r
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Algebra.Com's Answer #77119 by chitra(359)\"\" \"About 
You can put this solution on YOUR website!
Here i'm representing theta as x since writing theta everytime would be a tedious task.\r
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\n" ); document.write( "\n" ); document.write( "So the given problem can be written as: \r
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\n" ); document.write( "\n" ); document.write( "\"%28%28Cos+x+Sec+x+%29%2FCot+x%29\" = tan x\r
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\n" ); document.write( "\n" ); document.write( "We know that Cos and Sec are reciprocal of each other. And also tan and cot are also reciprocate of each other. That is \r
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\n" ); document.write( "\n" ); document.write( "\"Cos+x+=+%281%2FSec+x%29\"\r
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\n" ); document.write( "\n" ); document.write( "And \r
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\n" ); document.write( "\n" ); document.write( "\"+Tan+x+=+%281%2FCot+x%29\" \r
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\n" ); document.write( "\n" ); document.write( "so using the above in the given expression, we get: \r
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\n" ); document.write( "\n" ); document.write( "\"%28%28cosx+%2Asecx%29%2Fcotx%29\" \r
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\n" ); document.write( "\n" ); document.write( "==> \"%28Cosx%281%2FCosx%29%29%2F%281%2Ftanx%29\" \r
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\n" ); document.write( "\n" ); document.write( "The cos gets cancelled and we remain with \"%281%2F%281%2Ftan+x%29%29\" \r
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\n" ); document.write( "\n" ); document.write( "so that is nothing but tan x\r
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\n" ); document.write( "\n" ); document.write( "hence the solution.\r
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