document.write( "Question 1149797: Find the sum of the series 5/(sqrt2+sqrt1) + 5/(sqrt3+sqrt2) + 5/(sqrt4+sqrt3) + 5/(sqrt5+sqrt4)+...+ 5/(sqrt36)+(sqrt35) \n" ); document.write( "

Algebra.Com's Answer #771143 by ikleyn(52873) $\"\"$ $\"About$

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document.write( "HINT.  Multiply each denominator (and numerator) by the conjugate number to the denominator.\r\n" );
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document.write( "In each denominator, you will get the value of 1.\r\n" );
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document.write( "The numerators will form alternated sequence.\r\n" );
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document.write( "As a result, all intermediate terms will cancel each other, and you will get the combination \r\n" );
document.write( "of the last and the first terms as your answer.\r\n" );
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document.write( "ANSWER.  5*sqrt(36) - 5 = 5*6 - 5 = 25.\r\n" );
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\n" ); document.write( "\n" ); document.write( "See the lesson\r
\n" ); document.write( "\n" ); document.write( " - Amazing calculations with fractions that contain quadratic irrationalities in denominators\r
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\n" ); document.write( "\n" ); document.write( "Your problem is solved there with all detailed explanations.\r
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