document.write( "Question 1149780: Hi\r
\n" ); document.write( "\n" ); document.write( "a student was driving to school at 50mph. A quarter of the way he ran out of petrol. If he ran the rest of the way at 10mph what was his average speed.\r
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Algebra.Com's Answer #771112 by ikleyn(52765)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "a student was driving to school at 50mph. A quarter of the way he ran out of petrol.
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document.write( "Let \" d \" be the full distance.\r\n" );
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document.write( "Then the time to drive  \"t%5Bdrive%5D\" = \"%28%283%2F4%29%2Ad%29%2F50\" = \"%283d%29%2F200\" hours;\r\n" );
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document.write( "     the time to run    \"t%5Brun%5D\" = \"%28%281%2F4%29%2Ad%29%2F10\" = \"d%2F40\" hours.\r\n" );
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document.write( "\"V%5Baverage%5D\" = \"d%2F%28t%5Bdrive%5D%2Bt%5Brun%5D%29\" = \"d%2F%28%28%283d%29%2F200%29+%2B+d%2F40%29%29\" = \"1%2F%283%2F200%2B1%2F40%29\" = \"1%2F%283%2F200+%2B+5%2F200%29\" = \"1%2F%28%288%2F200%29%29\" = \"200%2F8\" = 25 miles per hour.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "After reading the note from @greenestamps:\r
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document.write( "    dear greenestamps, you are not right (!!)\r\n" );
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document.write( "    The problem says it directly and explicitly :  \" . . .  A quarter of the way  he ran out of petrol.\"\r\n" );
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document.write( "    Not a quarter of the time . . . \r\n" );
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\n" ); document.write( "\n" ); document.write( "My solution is correct (!)\r
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