document.write( "Question 105985: If the length of a rectangle is increased by 12 and the width is decreased by 8,the area is unchanged.The area is also unchanged if the original legth is increased by 5 and the original width is decreased by 4 .Find the original dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #77111 by alvinjohnburgos(11)\"\" \"About 
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if L = length of triangle
\n" ); document.write( " W = width of triangle
\n" ); document.write( "Then the area of the triangle would be:
\n" ); document.write( "eq.1)\"A+=+LW\"
\n" ); document.write( "the length of a rectangle is increased by 12 and the width is decreased by 8,the area is unchanged:
\n" ); document.write( "eq.2)\"A+=+%28L+%2B+12%29%28W+-+8%29\"
\n" ); document.write( "The area is also unchanged if the original length is increased by 5 and the original width is decreased by 4:
\n" ); document.write( "eq.3)\"A+=+%28L+%2B+5%29%28W+-+4%29\"
\n" ); document.write( "Substituting LW for A in eq2:
\n" ); document.write( "\"LW+=+%28L+%2B+12%29%28W+-+8%29\"
\n" ); document.write( "\"LW+=+LW++-+8L++%2B+12W+-+96\"
\n" ); document.write( "\"12W+-+8L+=+96\"
\n" ); document.write( "\"12W+=+96+%2B+8L\"
\n" ); document.write( "\"W+=+8+%2B+%282%2F3%29L\"
\n" ); document.write( "Substituting LW for A and (8 + (2/3)L) for W in eq3:
\n" ); document.write( "\"L%288+%2B+%282%2F3%29L%29+=+%28L+%2B+5%29%288+%2B+%282%2F3%29L+-+4%29\"
\n" ); document.write( "\"8L+%2B+%282%2F3%29L%5E2+=+%28L+%2B+5%29%284+%2B+%282%2F3%29L%29\"
\n" ); document.write( "\"8L+%2B+%282%2F3%29L%5E2+=+4L+%2B+%282%2F3%29L%5E2+%2B+20+%2B+%2810%2F3%29L\"
\n" ); document.write( "\"%282%2F3%29L+=+20\"
\n" ); document.write( "\"L+=+30\"
\n" ); document.write( "\"W+=+8+%2B+%282%2F3%29L\"
\n" ); document.write( "\"W+=+8+%2B+%282%2F3%29%2830%29\"
\n" ); document.write( "\"W+=+8+%2B+20+=+28\"
\n" ); document.write( "Dimensions of the triangle:
\n" ); document.write( "length is 30 units
\n" ); document.write( "width is 28 units
\n" ); document.write( "area is 840 square units
\n" ); document.write( "
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