document.write( "Question 1149770: If two fair dice are​ rolled, find the probability that the sum of the dice is 8​, given that the sum is greater than 7. \n" ); document.write( "
Algebra.Com's Answer #771101 by ikleyn(52814)\"\" \"About 
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document.write( "The numbers of appropriate outcomes are as follows.\r\n" );
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document.write( "     the sum of 8:  (2,6), (3,5), (4,4), (5,3), (6,2)   (5 outcomes)\r\n" );
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document.write( "     the sum of 9:  (3,6), (4,5), (5,4), (6,3)          (4 outcomes)\r\n" );
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document.write( "     the sum of 10:  (4,6), (5,5), (6,4)                (3 outcomes)\r\n" );
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document.write( "     the sum of 11:  (5,6), (6,5)                       (2 outcomes)\r\n" );
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document.write( "     the sum of 12:  (6,6)                              (1 outcome)\r\n" );
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document.write( "So, there are 5 + 4 + 3 + 2 + 1 = 15 outcomes with the sum greater than 7;\r\n" );
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document.write( "of them,  only 5 outcomes are \"favorable\".\r\n" );
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document.write( "Therefore, the conditional probability under the question is  P = \"5%2F15\" = \"1%2F3\".\r\n" );
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document.write( "In this problem, you can consider 15 outcomes as your space of events and 5 outcomes as the set of \"favorable\" events.\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see many other similar problems solved,  look into the lesson\r
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