document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101986>Question 101986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Alice is 10 years less than twice as old as Bonnie.  If the sum of the ages is 26.  Find the ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77110 by </B><A HREF=/tutors/aboutme.mpl?userid=BurningFlame_marc><B>BurningFlame_marc(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BurningFlame_marc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=BurningFlame_marc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello!\r<BR>\n" );
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document.write( "First we need to represent their age as variables. Let Bonnie's age be x and Alice's age be 2x-10.\r<BR>\n" );
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document.write( "Now we do the equation.<BR>\n" );
document.write( "2x-10+x=26\r<BR>\n" );
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document.write( "Solution:<BR>\n" );
document.write( "2x-10+x=26<BR>\n" );
document.write( "3x=36<BR>\n" );
document.write( "x=12\r<BR>\n" );
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document.write( "Final Answer: Bonnie is 12 years old and Alice is 24 years old.\r<BR>\n" );
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document.write( "Hope you understand my answer. </SPAN>\n" );
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