document.write( "Question 1149732: hi I need a help on this question. Can you please explain it
\n" ); document.write( "if you continue the pattern 2 0 1 8 2 0 1 8 2 0 1 8 what would be the 2018th number?
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Algebra.Com's Answer #771086 by ikleyn(52790) $\"\"$ $\"About$

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document.write( "Your sequence is PERIODIC.\r\n" );
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document.write( "The major period is these 4 terms {2 0 1 8}.\r\n" );
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document.write( "Divide 2018 by 4 to find the number of periods before 2018-th term\r\n" );
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document.write( "     = 504.5.\r\n" );
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document.write( "It means that there are 504 periods of 4 numbers before 2018-th term.\r\n" );
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document.write( "Exclude (mentally) these 504 periods.  504*4 = 2016.\r\n" );
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document.write( "Hence, the next two terms are 2 and 0 at 2017-th and 2018-th positions, respectively.\r\n" );
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document.write( "So, 0 is at the 2018-th position.     ANSWER\r\n" );
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