document.write( "Question 1149744: The cost of two ice cream cones is $2.25. A mother had in her a purse exactly two $2 coins, two $1 coins and two quarters. She took out two coins at random to pay for the coins. What is the probability that she did NOT have at least $2.25? \n" ); document.write( "
Algebra.Com's Answer #771080 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "There are nine possible outcomes:\r
\n" ); document.write( "\n" ); document.write( "(in cents):
\n" ); document.write( "25 and 25 x
\n" ); document.write( "25 and 100 x
\n" ); document.write( "25 and 200
\n" ); document.write( "100 and 25 x
\n" ); document.write( "100 and 100 x
\n" ); document.write( "100 and 200
\n" ); document.write( "200 and 25
\n" ); document.write( "200 and 100
\n" ); document.write( "200 and 200 \r
\n" ); document.write( "\n" ); document.write( "Only the four outcomes marked with an x add to less than 225 (= $2.25)\r
\n" ); document.write( "\n" ); document.write( "We can not say P(sum < 225) = 4/9, however, because not all the listed outcomes are equally likely. Here are the probabilities for the marked outcomes:\r
\n" ); document.write( "\n" ); document.write( "25 and 25 1/15
\n" ); document.write( "25 and 100 2/15
\n" ); document.write( "100 and 25 2/15
\n" ); document.write( "100 and 100 1/15
\n" ); document.write( " ----
\n" ); document.write( " 6/15 = \"+highlight%28+2%2F5+%29+\" or 40%\r
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