document.write( "Question 105968: \"+4x%5E2-x=3+\". solve for x \n" ); document.write( "
Algebra.Com's Answer #77103 by chitra(359)\"\" \"About 
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The given expression can be written as: \r
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\n" ); document.write( "\n" ); document.write( "\"+4x%5E2+-+x+=+3+\" \r
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\n" ); document.write( "\n" ); document.write( "Subtracting 3 from both the sides, we get: \r
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\n" ); document.write( "\n" ); document.write( "\"+4x%5E2+-+x+-+3+=+0+\" \r
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\n" ); document.write( "\n" ); document.write( "On factoring we get: \r
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\n" ); document.write( "\n" ); document.write( "\"+4x%5E2+-+4x+%2B+3x+-+3+=+0+\" \r
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\n" ); document.write( "\n" ); document.write( "\"4x%28x+-+1%29+%2B+3%28x+-+1%29+=+0+\" \r
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\n" ); document.write( "\n" ); document.write( "==> (4x + 3)(x - 1) = 0 \r
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\n" ); document.write( "\n" ); document.write( "==> (4x + 3) = 0 or (x - 1) = 0 \r
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\n" ); document.write( "\n" ); document.write( "==> x = -(3/4) or x = 1 \r
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\n" ); document.write( "\n" ); document.write( "thus the solution\r
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