document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105979>Question 105979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the amount of ice cream in a cone if the radius of the cone is 4cm and its height is 10cm. The ice cream fully fills the cone and the hemisphere of the ice cream on top has a radius of 4 cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77102 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> V(cone)=pi*r^2*h/3<BR>\n" );
document.write( "V(sphere)=(4/3)*pi*r^3 a hemisphere = 1/2 sphere<BR>\n" );
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document.write( "pi*4^2*10/3<BR>\n" );
document.write( "=pi*16*10/3<BR>\n" );
document.write( "=pi*160/3<BR>\n" );
document.write( "167.552<BR>\n" );
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document.write( "4/6*pi*4^3 we use 4/6 instead of 4/3 because it is 1/2 a sphere<BR>\n" );
document.write( "=(4/6)*pi*64<BR>\n" );
document.write( "=(128/3)*pi<BR>\n" );
document.write( "=134.041<BR>\n" );
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document.write( "167.552+134.041=301.593 cc<BR>\n" );
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document.write( "Ed<BR>\n" );
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