document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1149640>Question 1149640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle defined by the equation(x-6)^2. +(y-9)^2 is tangent to a line at the point (9,4).What is the equation of the circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770979 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Radius is needed.  You have a center of circle at  (6,9).  How far (Distance Formula) is  your point  (9,4) from (6,9)?  The circle will be of equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-6%29%5E2%2B%28y-9%29%5E2=%28yourradius%29%5E2 ALIGN=MIDDLE  ALT=\"%28x-6%29%5E2%2B%28y-9%29%5E2=%28yourradius%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );