document.write( "Question 1149579: If f(2x+1)=6x+2 what is f(x) \n" ); document.write( "
Algebra.Com's Answer #770941 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "I'm assuming f(x) is some linear function. If so, then,
\n" ); document.write( "f(x) = mx+b
\n" ); document.write( "m = slope
\n" ); document.write( "b = y intercept\r
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\n" ); document.write( "\n" ); document.write( "Replace every x input with (2x+1) and simplify
\n" ); document.write( "f(x) = mx+b
\n" ); document.write( "f(2x+1) = m(2x+1) + b
\n" ); document.write( "f(2x+1) = m*2x+m*1 + b
\n" ); document.write( "f(2x+1) = 2mx+m+b\r
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\n" ); document.write( "\n" ); document.write( "This is equal to 6x+2 since f(2x+1) = 6x+2 is given to us, so,
\n" ); document.write( "2mx+m+b = 6x+2
\n" ); document.write( "2mx+m+b = 6x+2\r
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\n" ); document.write( "\n" ); document.write( "Equating the two separate pieces has us see that
\n" ); document.write( "2mx = 6x
\n" ); document.write( "2m = 6
\n" ); document.write( "m = 3\r
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\n" ); document.write( "\n" ); document.write( "and also,
\n" ); document.write( "m+b = 2
\n" ); document.write( "3+b = 2 ... plug in m = 3
\n" ); document.write( "b = -1\r
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\n" ); document.write( "\n" ); document.write( "Therefore, m = 3 and b = -1, meaning we can say
\n" ); document.write( "f(x) = mx+b
\n" ); document.write( "f(x) = 3x+(-1)
\n" ); document.write( "f(x) = 3x-1\r
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\n" ); document.write( "\n" ); document.write( "note that replacing every x with (2x+1) leads to...
\n" ); document.write( "f(x) = 3x-1
\n" ); document.write( "f(2x+1) = 3(2x+1)-1
\n" ); document.write( "f(2x+1) = 3(2x)+3(1)-1
\n" ); document.write( "f(2x+1) = 6x+3-1
\n" ); document.write( "f(2x+1) = 6x+2
\n" ); document.write( "which helps confirm our answer.
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