document.write( "Question 1149604: In the diagram below, AC is the median of triangle ABD. Find the area of triangle ABD\r
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Algebra.Com's Answer #770937 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Given image
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\n" ); document.write( "Let point E be the midpoint of segment BC. The red triangle AEC has unknown height h and unknown base x
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\n" ); document.write( "Focusing solely on triangle AEC, we can use the pythagorean theorem to say\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2+%2B+b%5E2+=+c%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"h%5E2+%2B+x%5E2+=+17%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"h%5E2+%2B+x%5E2+=+289\"\r
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\n" ); document.write( "\n" ); document.write( "\"h%5E2+=+289-x%5E2\" subtract x^2 from both sides\r
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\n" ); document.write( "\n" ); document.write( "We'll use the last equation later on\r
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\n" ); document.write( "\n" ); document.write( "Mark triangle AED with another color. I'll use green. This triangle also has height h, but the base is now 3x
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\n" ); document.write( "The 3x is from the fact that\r
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\n" ); document.write( "\n" ); document.write( "EC = x
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\n" ); document.write( "ED = EC+CD = x+2x = 3x\r
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\n" ); document.write( "\n" ); document.write( "Once again, use the pythagorean theorem, but focus solely on triangle AED.\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2+%2B+b%5E2+=+c%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"h%5E2+%2B+%283x%29%5E2+=+27%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"h%5E2+%2B+9x%5E2+=+729\"\r
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\n" ); document.write( "\n" ); document.write( "\"289-x%5E2+%2B+9x%5E2+=+729\" Replace \"h%5E2\" with \"289-x%5E2\" (we're using \"h%5E2+=+289-x%5E2\" found earlier)\r
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\n" ); document.write( "\n" ); document.write( "\"289%2B8x%5E2+=+729\"\r
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\n" ); document.write( "\n" ); document.write( "\"8x%5E2+=+729-289\" Subtract 289 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"8x%5E2+=+440\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+440%2F8\" Divide both sides by 8\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+55\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%2855%29\" Apply square root to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"4x+=+4sqrt%2855%29\" Multiply both sides by 4\r
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\n" ); document.write( "\n" ); document.write( "The base of triangle ABD is exactly \"4%2Asqrt%2855%29\" units long\r
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\n" ); document.write( "\n" ); document.write( "Use that info to find the following value for h\r
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\n" ); document.write( "\n" ); document.write( "\"h%5E2+=+289-x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"h%5E2+=+289-55\"\r
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\n" ); document.write( "\n" ); document.write( "\"h%5E2+=+234\"\r
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\n" ); document.write( "\n" ); document.write( "\"h+=+sqrt%28234%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now compute the area of triangle ABD\r
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\n" ); document.write( "\n" ); document.write( "\"Area+=+%281%2F2%29%2A%28base%29%2A%28height%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"Area+=+%281%2F2%29%2A4sqrt%2855%29%2Asqrt%28234%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"Area+=+2%2Asqrt%2855%29%2Asqrt%28234%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"Area+=+2%2Asqrt%2855%2A234%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"Area+=+2%2Asqrt%2812870%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"Area+=+2%2Asqrt%289%2A1430%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"Area+=+2%2Asqrt%289%29%2Asqrt%281430%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"Area+=+2%2A3%2Asqrt%281430%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"Area+=+6%2Asqrt%281430%29\" Exact area\r
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\n" ); document.write( "\n" ); document.write( "\"Area+=+226.892\" Approximate area\r
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\n" ); document.write( "\n" ); document.write( "Units are in square cm, often written as \"cm%5E2\"
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