document.write( "Question 15536: The length of a rectangle is 2cm less than 7 times the width. The perimeter is 60cm. Find the width and length.\r
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document.write( "The second problem is:
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document.write( "The first side of a triangle is 8m shorter than the second side. The third side is 4times as long as the first side. The perimeter is 26m. Find the length of each side.\r
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document.write( "Thank you so much for your help. I am in desperate need with college algebra.
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Algebra.Com's Answer #7709 by pwac(253)![]() ![]() ![]() You can put this solution on YOUR website! OK Problem 1) \n" ); document.write( "We have to derive an equation:Perimeter of rectangle is \n" ); document.write( "2 x width+2 x length \n" ); document.write( "If we have width = x \n" ); document.write( "The length will be 7x-2 \n" ); document.write( "So our equation will be: \n" ); document.write( "2x+2(7x-2)=60 Multiply expression in bracket by 2 \n" ); document.write( "2x+14x-4=60 Rearrange to get: \n" ); document.write( "16x=64 Divide both sides by 16 \n" ); document.write( "x=4cm which is the width \n" ); document.write( "Length is (7x4)-2=26\r \n" ); document.write( "\n" ); document.write( "Problem 2) \n" ); document.write( "Again need to derive an equation: \n" ); document.write( "Let second side=x \n" ); document.write( "so first side=x-8 and \n" ); document.write( "third=4(x-8).So our equation will be: \n" ); document.write( "x-8+x+4(x-8)=26 get rid of brackets by multiplying by the 4 \n" ); document.write( "x-8+x+4x-32=26 \n" ); document.write( "6x-40=26 Add 40 to both sides \n" ); document.write( "6x=66 \n" ); document.write( "x=11 So 1st side=3m,2nd side=11m and 3rd=12m \n" ); document.write( "hope this helps \n" ); document.write( "Pete \n" ); document.write( " |