document.write( "Question 105583: brooke walks 2 km/hr slower than her older sister Adrianna. If Brooke can walk 12 km in the same amount of time that Adrianne can walk 18 km, find their speeds \n" ); document.write( "
Algebra.Com's Answer #77089 by ankor@dixie-net.com(22740)\"\" \"About 
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brooke walks 2 km/hr slower than her older sister Adrianna. If Brooke can walk 12 km in the same amount of time that Adrianne can walk 18 km, find their speeds.
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\n" ); document.write( "Let x = walking speed of B
\n" ); document.write( "Then
\n" ); document.write( "(x+2) = walking speed of A
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\n" ); document.write( "Write a time equation: Time = distance/speed
\n" ); document.write( "A's time = B's time
\n" ); document.write( "\"18%2F%28%28x%2B2%29%29\" = \"12%2Fx\"
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\n" ); document.write( "Cross multiply:
\n" ); document.write( "18x = 12(x+2)
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\n" ); document.write( "18x = 12x + 24
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\n" ); document.write( "18x - 12x = 24
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\n" ); document.write( "6x = 24
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\n" ); document.write( "x = \"24%2F6\"
\n" ); document.write( "x = 4 km/h is B's speed
\n" ); document.write( "then
\n" ); document.write( "4 + 2 = 6 km/h is A's speed
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\n" ); document.write( "Check solutions by finding if they are equal times
\n" ); document.write( "18/6 = 3 hr
\n" ); document.write( "12/4 = 3 hr; confirms our solutions\r
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