document.write( "Question 1149530: Antonette age is 3 years older than her sister. 6 years ago her sister is 4 times antonette age. How old is antonette? \n" ); document.write( "
Algebra.Com's Answer #770870 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The statement of the problem is faulty; it says now Antonette is older and 6 years ago her sister was older. \n" ); document.write( "I will ignore that and solve the problem as it was probably intended -- with Antonette older. \n" ); document.write( "Using formal algebra... which I will assume is what you are learning to do by asking this question.... \n" ); document.write( "Let the sister's age be x \n" ); document.write( "Then Antonette's age is x+3 \n" ); document.write( "Then 6 years ago the sister's age was x-6, and Antonette's age was (x+3)-6 = x-3. \n" ); document.write( "Then, since 6 years ago Antonette was 4 times as old as her sister, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: Antonette's age is x+3 = 10 years \n" ); document.write( "CHECK: 6 years ago, Antonette was 10-6 = 4 years old and her sister was 7-6 = 1 year old; Antonette was 4 times as old as her sister. \n" ); document.write( "Note that, if a formal algebraic solution is not required, the question can be answered quickly with a little logical reasoning and simple arithmetic. \n" ); document.write( "If the difference between their ages is 3 years, then when Antonette was 4 times as old as her sister, their ages had to be 4 and 1. \n" ); document.write( "And since that was 6 years ago, their ages now are 10 and 7. \n" ); document.write( "While knowing how to solve problems like this with formal algebra is important, solving them using logical reasoning is also good mental exercise. \n" ); document.write( " \n" ); document.write( " |