document.write( "Question 1149483: Luis invested $6000 in two different accounts. One earned 4% and the other earned 7%. He earned a total of $375 in interest in one year. How much was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #770831 by greenestamps(13198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If an algebraic solution is not required, then compare the amount of work required by this alternative method with that required with the standard algebraic solution shown by the other tutor. \n" ); document.write( "$6000 all at 4% --> $240 interest \n" ); document.write( "$6000 split between 4% and 7% --> $375 interest \n" ); document.write( "$6000 all at 7% --> $420 interest \n" ); document.write( "$375 is 3/4 of the way from $240 to $420. ($240 to $375 is $135; $240 to $420 is $180; 135/180 = 3/4. Picture the three numbers on a number line if it helps you see the 3/4.) \n" ); document.write( "That means 3/4 of the investment is at the higher rate. \n" ); document.write( "ANSWER: 3/4 of $6000, or $4500, at 7%; the other $1500 at 4%. \n" ); document.write( "CHECK: \n" ); document.write( ".07(4500)+.04(1500) = 315+60 = 375 \n" ); document.write( " \n" ); document.write( " |