document.write( "Question 105932: Robert is 1/2 as old as his father. Twelve years ago he was 1/3 as old as his father was then. Find their present ages \n" ); document.write( "
Algebra.Com's Answer #77083 by Earlsdon(6294)\"\" \"About 
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Start by letting R = Robert's present age and F = Father's present age.
\n" ); document.write( "From the problem you can write:
\n" ); document.write( "1) \"R+=+%281%2F2%29F\" \"Robert (R) is half as old as his father (F)\"
\n" ); document.write( "2) \"R-12+=+%281%2F3%29%28F-12%29\" \"Twelve years ago, he was 1/3 as old as his father was then\"
\n" ); document.write( "So now you have a system of equations with two unknowns (R and F) and you can use any of the accepted methods for solving these for R and F.
\n" ); document.write( "You can simplify these equations by clearing the fractions.
\n" ); document.write( "1) \"R+=+%281%2F2%29F\" Multiply through by 2.
\n" ); document.write( "1a) \"2R+=+F\"
\n" ); document.write( "2) \"R-12+=+%281%2F3%29%28F-12%29\" Multiply through by 3.
\n" ); document.write( "2a) \"3R-36+=+F-12\" Now substitute the F from the simplified equation 1a) into the simplified equation 2a).
\n" ); document.write( "\"3R-36+=+2R-12\" Simplify and solve for R by subtracting 2R from both sides.
\n" ); document.write( "\"R-36+=+-12\" Add 36 to both sides.
\n" ); document.write( "\"R+=+24\" This is Robert's present age.
\n" ); document.write( "\"F+=+2R\"
\n" ); document.write( "\"F+=+2%2824%29\"
\n" ); document.write( "\"F+=+48\" This is the father's present age.
\n" ); document.write( "Check:
\n" ); document.write( "\"R+=+%281%2F2%29F\"
\n" ); document.write( "\"24+=+%281%2F2%29%2848%29\"
\n" ); document.write( "\"24+=+24\" OK, and...
\n" ); document.write( "\"R-12+=+%281%2F3%29%28F-12%29\"
\n" ); document.write( "\"24-12+=+%281%2F3%29%2848-12%29\"
\n" ); document.write( "\"12+=+%281%2F3%29%2836%29\"
\n" ); document.write( "\"12+=+12\" OK
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