document.write( "Question 1149492: Three peaches and a banana cost 98 cents.
\n" ); document.write( "Six peaches and a banana cost $1.79.
\n" ); document.write( "How much does one banana cost? \n" ); document.write( "
Algebra.Com's Answer #770828 by greenestamps(13209)\"\" \"About 
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\n" ); document.write( "Using logical reasoning....

\n" ); document.write( "(1) Compare the two purchases to determine how much the additional three peaches cost.

\n" ); document.write( "(2) You know the cost of three peaches and one banana; use your answer from (1) to determine the cost of the banana.

\n" ); document.write( "Algebraically....
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document.write( "                 6p+1b = 179\r\n" );
document.write( "                 3p+1b =  98\r\n" );
document.write( "                 -----------\r\n" );
document.write( "    difference:  3p    =  81\r\n" );
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document.write( "Then....\r\n" );
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document.write( "                3p+1b = 98\r\n" );
document.write( "                3p    = 81\r\n" );
document.write( "                ----------\r\n" );
document.write( "   difference:     1b = 17

\n" ); document.write( "That solution using algebra is step for step the same as the preceding solution using logical reasoning.

\n" ); document.write( "Here is an alternative algebraic solution which probably isn't the way you would solve the problem using logical reasoning; but it makes the algebraic solution easier.

\n" ); document.write( "(1) Double the first purchase to get 6 peaches and 2 bananas for 2($0.98) = $1.96. Then compare the two purchases:
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document.write( "                 6p+2b = 196\r\n" );
document.write( "                 6p+1b = 179\r\n" );
document.write( "                 -----------\r\n" );
document.write( "    difference:     1b =  17


\n" ); document.write( "That path to the solution gets you to the final answer in fewer steps.

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