document.write( "Question 1149491: In order to determine the age of a piece of wood, the amount of carbon-14 was measured. It was determined that the wood had lost 33.1% of its carbon-14. How old is this piece of wood? \n" ); document.write( "
Algebra.Com's Answer #770824 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "If 33.1% has been lost, 66.9% remains. So we need to know how many half-lives have passed if 66.9% of the Carbon-14 remains.

\n" ); document.write( "\"%28.5%29%5Ex+=+0.669\"
\n" ); document.write( "\"x%2Alog%28%28.5%29%29+=+log%28%28.669%29%29\"
\n" ); document.write( "\"x+=+log%28%280.669%29%29%2Flog%28%280.5%29%29\"
\n" ); document.write( "x = 0.57992... or approximately 0.58.

\n" ); document.write( "You didn't give the half-life of Carbon-14, so we can't get a final answer.\n" ); document.write( "Multiply the half-life in years by 0.58 to find the age of the piece of wood in years.

\n" ); document.write( "---------------------------------------------------------------

\n" ); document.write( "For tutor @ikleyn....

\n" ); document.write( "Something is wrong somewhere in your calculations. 10000 years is more than the half life; 66.9% will not still remain....
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );