document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15536>Question 15536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2cm less than 7 times the width. The perimeter is 60cm. Find the width and length.\r<BR>\n" );
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document.write( "The second problem is:<BR>\n" );
document.write( "The first side of a triangle is 8m shorter than the second side. The third side is 4times as long as the first side. The perimeter is 26m. Find the length of each side.\r<BR>\n" );
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document.write( "Thank you so much for your help. I am in desperate need with college algebra.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7708 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7708\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2cm less than 7 times the width. The perimeter is 60cm. Find the width and length.<BR>\n" );
document.write( "let length be =L<BR>\n" );
document.write( "let width be  = W<BR>\n" );
document.write( "7 times width =7W<BR>\n" );
document.write( " 2 cm. less than above = 7W-2 = L<BR>\n" );
document.write( "  perimeter =2L+2W = 60 <BR>\n" );
document.write( "  2*(7W-2)+2W = 60 <BR>\n" );
document.write( "   14W+2W=60+2*2=64<BR>\n" );
document.write( "16W = 64 <BR>\n" );
document.write( "  W =64/16 = 4<BR>\n" );
document.write( "  L=7*4-2 = 26<BR>\n" );
document.write( "  SECOND PROBLEM\r<BR>\n" );
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document.write( "The first side of a triangle is 8m shorter than the second side. The third side is 4times as long as the first side. The perimeter is 26m. Find the length of each side. <BR>\n" );
document.write( "Let the first side =x<BR>\n" );
document.write( "let the second side =y<BR>\n" );
document.write( "let the third side =z<BR>\n" );
document.write( "8m shorte than second side = y-8 = x OR y = x+8<BR>\n" );
document.write( "4 times the first side =4*x= z<BR>\n" );
document.write( "perimeter =x+y+z = 26 <BR>\n" );
document.write( "x+(x+8)+4*x = 26<BR>\n" );
document.write( "x+x+4x=26-8 = 18<BR>\n" );
document.write( "6x = 18 <BR>\n" );
document.write( "x=18/6 = 3<BR>\n" );
document.write( "y= 3+8 = 11<BR>\n" );
document.write( "z=4*3 = 12 \r<BR>\n" );
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