document.write( "Question 1149472: Find the mean and standard deviation for a binomial distribution with 912 trials and a probability of success of 0.21 and enter the answers below. Round each value to two decimal places.\r
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document.write( "Mean:\r
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Algebra.Com's Answer #770789 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! mean is np=912*0.21=191.52 \n" ); document.write( "variance is np(1-p)=912.52*0.79=151.3008 \n" ); document.write( "sd is sqrt (V)=12.30 \n" ); document.write( " |