document.write( "Question 105860: ok so this is my equation.
\n" ); document.write( "and i get it and all its just i cant get it to work
\n" ); document.write( "but the teacher told us that i had to be in whole answers\r
\n" ); document.write( "\n" ); document.write( "-2x+y+z=-2
\n" ); document.write( "5x+3y+3z=71
\n" ); document.write( "4x-2y-3z=1\r
\n" ); document.write( "\n" ); document.write( "this is what i have tried so far..\r
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\n" ); document.write( "\n" ); document.write( "5x+3y+3z=71
\n" ); document.write( "4x-2y-3z=1
\n" ); document.write( "-----------
\n" ); document.write( "9x+y=72\r
\n" ); document.write( "\n" ); document.write( "and then from there i have tried them all, and it just wont come out.!\r
\n" ); document.write( "\n" ); document.write( "please help me.!\r
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Algebra.Com's Answer #77078 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
(3 times the first equation) added to the third equation gives -2x+y=-5 , so y=2x-5
\n" ); document.write( "...substitute into the equation you found to get x\r
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\n" ); document.write( "\n" ); document.write( "9x+(2x-5)=72\r
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\n" ); document.write( "\n" ); document.write( "use the x-value to find y; and then use the x and y values to find z
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