document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105926>Question 105926</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help!\r<BR>\n" );
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document.write( "A rectangle has an area of 192 and a perimeter of 56.  Find the dimensions for length and width.  (A = Lw & P = 2L + 2W)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77077 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) L*w=192<BR>\n" );
document.write( "B) 2L+2w=56<BR>\n" );
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document.write( "B) 2L=56-2w subtract 2w from each side.<BR>\n" );
document.write( "L=28-w divide each side by 2.<BR>\n" );
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document.write( "A) w(28-w)=192 replace L with 28-w<BR>\n" );
document.write( "28w-w^2=192<BR>\n" );
document.write( "-w^2+28w-192=0<BR>\n" );
document.write( "w^2-28w+192=0 multiply each side by -1<BR>\n" );
document.write( "(w-12)(w-16)=0<BR>\n" );
document.write( "w=12, w=16<BR>\n" );
document.write( "Either number can be L and the other can be w.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "12*16=192<BR>\n" );
document.write( "24+32=56<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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