document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105847>Question 105847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have to solve each equation for y in terms of x.\r<BR>\n" );
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document.write( "-2x+3y=-12\r<BR>\n" );
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document.write( "And the answer could be...\r<BR>\n" );
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document.write( "1:y=5/2x+1/2\r<BR>\n" );
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document.write( "2:y=1/2x+3\r<BR>\n" );
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document.write( "3:neither\r<BR>\n" );
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document.write( "But if it is neither then i have to figure it out myself....<BR>\n" );
document.write( "Im sorry but i dont know if this is an equition or whatever!!!\r<BR>\n" );
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document.write( "Please help me out just a little:]<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77070 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> neither looks good, so...<BR>\n" );
document.write( "you need to get the y by itself \r<BR>\n" );
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document.write( "...adding 2x gives 3y=2x-12\r<BR>\n" );
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document.write( "...dividing by 3 will get the y by itself </SPAN>\n" );
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