document.write( "Question 1149301: Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the high temperature of 53 degrees occurs at 4 PM and the average temperature for the day is 45 degrees. Find the temperature, to the nearest degree, at 8 AM. \n" ); document.write( "
Algebra.Com's Answer #770688 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "We have an average temperature of 45 degrees and a high of 53 degrees. That makes the midline 45 and the amplitude 8. \n" ); document.write( "We could spend some time trying to figure out how to get a graph in which x=0 corresponds to midnight. However; that is not necessary. We can use any sinusoidal function we want, as long as we understand which part of the graph corresponds to what hour of the day. \n" ); document.write( "So with midline 45 and amplitude 8, let's choose a simple function: \n" ); document.write( " \n" ); document.write( "A graph (showing 1.5 periods, from -pi to 2pi).... \n" ); document.write( " \n" ); document.write( "The time at which we are to find the temperature, 8 AM, is 8 hours before 4 PM, which is the time when the temperature is maximum. 8 hours is 1/3 of a day, so we want to find the temperature 1/3 of a cycle before 4 PM. \n" ); document.write( "Since we are using a sine function with no horizontal shift, the time of maximum temperature, 4 PM, corresponds to 1/4 of the way through a cycle, at pi/2. \n" ); document.write( "We want to go back 1/3 of a cycle, or (2/3)pi, from pi/2; that puts us at -pi/6. \n" ); document.write( "That makes it easy to find the temperature at 4 AM without a calculator: \n" ); document.write( " \n" ); document.write( "The temperature at 4 AM is 41 degrees. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |