document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1149283>Question 1149283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A point moves along a straight path. The function <BR>\n" );
document.write( "f(t)=log3(t)<BR>\n" );
document.write( " determines the distance (in meters) the point has traveled in terms of the number of seconds <BR>\n" );
document.write( "t<BR>\n" );
document.write( " since the point started moving.\r<BR>\n" );
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document.write( "How far has the point traveled 22 seconds after it started moving?\r<BR>\n" );
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document.write( " meters   \r<BR>\n" );
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document.write( "If the point has traveled 2 meters, how many seconds have elapsed since it started moving?\r<BR>\n" );
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document.write( " seconds   \r<BR>\n" );
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document.write( "Write a function <BR>\n" );
document.write( "f^-1<BR>\n" );
document.write( " that determines the number of seconds that have elapsed since the particle started moving in terms of the distance (in meters) the particle has traveled, <BR>\n" );
document.write( "d.f^−1(d)=<BR>\n" );
document.write( "   \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770653 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when t=22, the point has moved log 66 m or 1.819 m<BR>\n" );
document.write( "2= log 3 t<BR>\n" );
document.write( "raise to 10th power<BR>\n" );
document.write( "100=3t<BR>\n" );
document.write( "t=100/3 seconds\r<BR>\n" );
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document.write( "The inverse function is t=log (3y<BR>\n" );
document.write( "10^t=3y<BR>\n" );
document.write( "y=(1/3)(10^t)\r<BR>\n" );
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document.write( "NOTE: I am assuming this is log 3t not log(3) t </SPAN>\n" );
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