document.write( "Question 1149270: Bob leaves Pittsburgh traveling west. Jim leaves from the same point two hours later and travels the same route at 18 miles per hour faster than bob. If Jim wants to catch up four hours after he leaves, how fast will he have to go? \n" ); document.write( "
Algebra.Com's Answer #770614 by ankor@dixie-net.com(22740)\"\" \"About 
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Bob leaves Pittsburgh traveling west.
\n" ); document.write( " Jim leaves from the same point two hours later and travels the same route at 18 miles per hour faster than bob.
\n" ); document.write( " If Jim wants to catch up four hours after he leaves, how fast will he have to go?
\n" ); document.write( ";
\n" ); document.write( "let s = Jim's speed
\n" ); document.write( "then
\n" ); document.write( "(s-18) = Bob's speed
\n" ); document.write( ":
\n" ); document.write( "When J catch's B it will be 6 hrs after B departed (2 + 4)
\n" ); document.write( "They will have traveled the same distance
\n" ); document.write( "Write a distance equation, dist = time * speed
\n" ); document.write( "6(s-18) = 4s
\n" ); document.write( "6s - 108 = 4s
\n" ); document.write( "6s - 4s = 108
\n" ); document.write( "2s = 108
\n" ); document.write( "s = 108/2
\n" ); document.write( "s = 54 mph
\n" ); document.write( ":
\n" ); document.write( "Check find the actual dist each traveled B's speed 54 - 18 = 36 mph
\n" ); document.write( "6 * 36 = 216 mi
\n" ); document.write( "4 * 54 = 216 \n" ); document.write( "
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