document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1149185>Question 1149185</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the diagram below, ABCD is a parallelogram with AB=42 cm. Arc AD is a semi-circle. The area of the parallelogram is 504cm2, and angle ADC = 60 degrees. Find the area of the shaded region in cm2. \r<BR>\n" );
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document.write( "Diagram: https://imgur.com/a/JyfuGQN </SPAN>\n" );
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document.write( "Let x be the length of AD, the base of the parallelogram.<br><BR>\n" );
document.write( "The height of the parallelogram is<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=42%2Asin%2860%29+=+42%2A%28sqrt%283%29%2F2%29+=+21%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"42%2Asin%2860%29+=+42%2A%28sqrt%283%29%2F2%29+=+21%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "The area, 504, is base times height:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=504+=+%28x%29%2821%2Asqrt%283%29%29 ALIGN=MIDDLE  ALT=\"504+=+%28x%29%2821%2Asqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+504%2F%2821%2Asqrt%283%29%29+=+24%2Fsqrt%283%29+=+8%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"x+=+504%2F%2821%2Asqrt%283%29%29+=+24%2Fsqrt%283%29+=+8%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "AD is the diameter of the semicircle, length x=8*sqrt(3); the radius of the semicircle is 4*sqrt(3).  The area of the semicircle is<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29%28pi%29%284%2Asqrt%283%29%29%5E2+=+24pi ALIGN=MIDDLE  ALT=\"%281%2F2%29%28pi%29%284%2Asqrt%283%29%29%5E2+=+24pi\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
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