document.write( "Question 1149233: Two planes, which are 2160 miles apart, fly toward each other. Their speeds differ by 40mph. If they pass each other in 4 hours, what is the speed of each?
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Algebra.Com's Answer #770578 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "Using algebra....

\n" ); document.write( "Let the speeds be x and x+40. Then

\n" ); document.write( "\"4%28x%29%2B4%28x%2B40%29+=+2160\"

\n" ); document.write( "Solve using basic algebra....

\n" ); document.write( "Using logical analysis and simple mental arithmetic....

\n" ); document.write( "The combined speed is 2160/4 = 540.
\n" ); document.write( "If the two speeds were the same, they would each be 270; 270+270=540.
\n" ); document.write( "To get two speeds that differ by 40mph, add 20mph to one speed and subtract 20mph from the other.

\n" ); document.write( "ANSWER: 270+20 = 290mph and 270-20 = 250mph

\n" ); document.write( "CHECK:
\n" ); document.write( "\"4%28290%29%2B4%28250%29+=+1160%2B1000+=+2160\"

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