document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1149200>Question 1149200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Square ABCD is inscribed in a circle. Find the ratio of the area of the square to the area of the circle. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770576 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13208)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770576\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Consider the diagonals of the square.  Each is a diameter of the circle.  Let r be the radius of the circle.<br><BR>\n" );
document.write( "The diagonals of the square divide the square into four 45-45-90 right triangles.  The side length of the square (the hypotenuse of one of those right triangles) is sqrt(2) times the length of the radius of the circle.<br><BR>\n" );
document.write( "The area of the square is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2+=+%28r%2Asqrt%282%29%29%5E2+=+2r%5E2 ALIGN=MIDDLE  ALT=\"s%5E2+=+%28r%2Asqrt%282%29%29%5E2+=+2r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "The area of the circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28pi%29r%5E2 ALIGN=MIDDLE  ALT=\"%28pi%29r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "The ratio of the two areas is<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282r%5E2%29%2F%28%28pi%29r%5E2%29+=+2%2F%28pi%29 ALIGN=MIDDLE  ALT=\"%282r%5E2%29%2F%28%28pi%29r%5E2%29+=+2%2F%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
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