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\n" ); document.write( "There are multiple options for how to solve this problem. For a beginning algebra class, something like this might be appropriate.
\n" ); document.write( "Let x = first number
\n" ); document.write( "let y = second number
\n" ); document.write( "The sum of the two numbers is 35: x+y=35 (1)
\n" ); document.write( "Twice the first is equal to 5 times the second: 2x = 5y (2)
\n" ); document.write( "Solve either equation for one variable in terms of the other and substitute in the other equation. One option would be
\n" ); document.write( "y = 35-x
\n" ); document.write( "and then
\n" ); document.write( "2x = 5(35-x)
\n" ); document.write( "Solve that equation for x and then substitute that value in one of the original equations to find y.
\n" ); document.write( "My personal preference for solving this problem would be this....
\n" ); document.write( "\"twice the first number is equal to 5 times the second number\"
\n" ); document.write( "--> the two numbers are in the ratio 5:2
\n" ); document.write( "--> let the two numbers be 5x and 2x
\n" ); document.write( "Then
\n" ); document.write( "5x+2x = 35
\n" ); document.write( "7x = 35
\n" ); document.write( "x = 5
\n" ); document.write( "The two numbers are 5x=25 and 2x=10.
\n" ); document.write( "Hopefully you will get responses from other tutors showing different methods....
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