document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1149205>Question 1149205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the radius, in cm, of the large circle if the radius of the smaller circle is 5 sqrt3 cm. The angle formed by the two radii at the center is 60 degrees.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770544 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The two radii, along with a chord of the large circle tangent to the small circle, form a 30-60-90 right triangle.<br><BR>\n" );
document.write( "The hypotenuse of the triangle is the radius of the large circle; the short leg of the triangle is the radius of the small circle.<br><BR>\n" );
document.write( "In a 30-60-90 right triangle, the length of the hypotenuse is twice the length of the short leg.<br><BR>\n" );
document.write( "Since the length of the short leg is 5*sqrt(3) cm, the radius of the large circle is 10*sqrt(3) cm.<br><BR>\n" );
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