document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1149168>Question 1149168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangle is 42 cm and the area is 90 square cm, then what are the dimensions of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770514 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangle is 42 cm and the area is 90 square cm, then what are the dimensions of the rectangle?<BR>\n" );
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document.write( "P = 2L + 2W = 42<BR>\n" );
document.write( "L + W = 21<BR>\n" );
document.write( "L*W = 90<BR>\n" );
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document.write( "Find a pair of factors of 90 with a sum of 21.<BR>\n" );
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