document.write( "Question 1149089: Where does the graph of v(x) = log5 (x) and its inverse intersect?\r
\n" ); document.write( "\n" ); document.write( "we tried using a graphing calc and it says no solution. we are not very certain if it correct. thank you! \n" ); document.write( "

Algebra.Com's Answer #770468 by math_helper(2461) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+f%28x%29+=+log%285%2C+%28x%29%29+\"$
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\n" ); document.write( "\n" ); document.write( " $\"+f%5E-1%28x%29+=+5%5Ex+\"$
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\n" ); document.write( "\n" ); document.write( "One way you can see they can not be equal is by thinking about x approaching zero from the negative side (i.e. consider negative x values). Only $\"f%5E-1%28x%29\"$ is defined on that region, and when x=0, $\"f%5E-1%280%29+=+1\"$ . Now as x takes on positive values, $\"f%5E-1%28x%29\"$ becomes larger and larger positive values: ( $\"f%5E-1%282%29=25\"$ , $\"f%5E-1%283%29=125\"$ , etc.). Looking at $\"f%28x%29\"$ , it is only defined on x>0 and is negative for x < 1 and then reaches 0 at x=1, 1 at x=5, and then slowly rises for larger x values.
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\n" ); document.write( "\n" ); document.write( "A picture is worth a 1000 words:
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