document.write( "Question 1149085: A midwestern music competition awarded 43 ribbons. The number of blue ribbons awarded was 2 less than the number of white ribbons. The number of red ribbons was 3 more than the number of white ribbons. How many of each kind of ribbon was awarded. \n" ); document.write( "

Algebra.Com's Answer #770414 by ikleyn(52788) $\"\"$ $\"About$

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document.write( "Let x be the number of white ribbons.\r\n" );
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document.write( "Then the number of blue ribbon was  (x-2),  while the number of red ribbons was (x+3).\r\n" );
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document.write( "The total number equation\r\n" );
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document.write( "    x + (x-2) + (x+3) = 43.\r\n" );
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document.write( "Simplify and solve\r\n" );
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document.write( "    3x + 1 = 43\r\n" );
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document.write( "    3x     = 43 - 1 = 42\r\n" );
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document.write( "     x     = 42/3 = 14.\r\n" );
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document.write( "ANSWER.  14 white ribbons,  14-2 = 12 blue ribbons  and 14+3 = 17 red ribbons.\r\n" );
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document.write( "CHECK.  14 + 12 + 17 = 43.    ! Correct !\r\n" );
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